This is the last part for the Problems on Trains aptitude question and answers. This part consists a set of 10 questions. We also attached pdf at the end of this post. Download the aptitude pdf for offline study.

**Problems on Trains- Aptitude Question and Answer Part 4**

1) A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

- 120m
- 180m
- 324m
- 150m

**Answer**: Option D

**Explanation: **

Speed= ( 60 * 5/18 )m/sec = ( 50/ 3 )m/sec.

Length of train = ( Speed * Time ) = ( ( 50/3) * 9 )m = 150 m.

2) A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is :

A) 45 km/hr

B) 50 km/hr

C) 54 km/hr

D) 55 km/hr

**ANSWER **: Option B

**EXPLANATION :
**Speed of the train relative to man = ( 125/10 )m/sec

= ( 25/2 )m/sec.

= ( (25/2) *(18/5) )km/hr

= 45 km/hr.

Let the Speed of the train be x km/hr. Then, relative speed = (x-5) km/hr. Therefore, x-5 = 45 => x=50 km/hr.

3) The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:

A.200 m

B.225 m

C.245 m

D.250 m

**Answer: **Option C

**Explanation:
**Speed = [45 x(5/18)] m/sec =( 25/2 )m/sec. Time = 30 sec.

Let the length of bridge be x metres.

Then, [ ( 130 + x ) / 30 ] = ( 25/2 )

=> 2(130 + x) = 750

=> x = 245 m.

4) Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

A. 1 : 3

B. 3 : 2

C. 3 : 4

D. None of these

**Answer**: Option B

**Explanation:
**Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

( 27x + 17y ) / (x+ y )= 23

=> 27x + 17y = 23x + 23y

=> 4x=6y

=> ( x/y ) = ( 3/2 )

5) A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

A.120 m

B.240 m

C.300 m

D.None of these

**Answer: **Option B

**Explanation:
**Speed = [ 54 x (5/18)] m/sec = 15 m/sec. Length of the train = (15 x 20)m = 300 m. Let the length of the platform be x metres. Then, [ (x + 300)/36 ] = 15

=> x + 300 = 540

=> x = 240 m.

6) A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

A.65 sec

B.89 sec

C.100 sec

D.150 sec

**Answer: **Option B

**Explanation:
**Speed = (240/24) m/sec = 10 m/sec.

Required time =[ (240 + 650)/10) ] sec = 89 sec.

7)Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

A.50 m

B.72 m

C.80 m

D.82 m

**Answer: **Option A

**Explanation: **

Let the length of each train be x metres. Then, distance covered = 2x metres. Relative speed = (46 – 36) km/hr

=[ 10 x(5/18) ] m/sec

=( 25/9 ) m/sec (2x)/36 =25/9 => 2x = 100

=> x = 50.

8) A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

A.40 sec

B.42 sec

C.45 sec

D.48 sec

**Answer: **Option A

**Explanation:
**Formula for converting from km/hr to m/s:

Therefore, Speed =[ 45 x( 5/18) m/sec=( 25/2 )m/sec. Total distance to be covered = (360 + 140) m = 500 m. Formula for finding Time =( Distance/Speed ) Required time = [ (500 x 2)/25 ] sec = 40 sec.

9) Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

A.36

B.45

C.48

D.49

**Answer: **Option C

**Explanation:
**Relative speed = (60+ 90) km/hr

=[ 150 * (5/18) ] m/sec

=(125/3) m/sec.

Distance covered = (1.10 + 0.9) km = 2 km = 2000 m. Required time =[ 2000 x ( 3/125) ] sec = 48 sec.

10) A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

A.3.6 sec

B.18 sec

C.36 sec

D.72 sec

**Answer: **Option C

**Explanation:
**Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr. =[ 36 x( 5/18 ) m/sec

= 10 m/sec.

Distance to be covered = (240 + 120) m = 360 m.

Time taken =( 360/10 ) sec = 36 sec

**Download Problems on Trains Aptitude Pdf Part 4**

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**Also Download the Previous parts**

Problems on trains aptitude Questions with answers – Part 1